H. C. Verma, Chapter 3, Question 8 The figure shows the graph of velocity versus

time for a particle going along the x-axis. Find (a) the acceleration, (b) the distance

travelled in 0 to 10 seconds and (c) the displacement in 0 to 10 seconds. Acceleration is given by change in velocity

divided by time. As the final velocity is 8 meter per second and initial velocity is

2 meter per second, the change in velocity is 6 meters per second. Total time taken is

10 seconds. Therefore, acceleration is equal to 6 by 10 or 0.6 meter per second square.

This is answer to part A of the question. In a velocity time graph, displacement is

equal to the area under the graph. Therefore, displacement in this case is area of the shaded

region. The area of trapezium is half into sum of parallel sides into distance between

the parallel sides. Therefore, displacement in this case is half into 2 plus 8 into 10.

That is 50 meters. Since the velocity of the particle does not change its direction during

the motion, the distance and displacement is equal. Therefore, both the displacement

and distance is 50 meters. This is answer to part b and part c of the question. In order to request solution to any question

from H. C. Verma book, post the question number and chapter number in comments below. LIke

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Sir hcv question no. 32 of chapter 10

thank you

thank you sir

Sir,l wasn't class 9 physics HC verma chapter 2 solution by 2nd April

l wan't u to upload hc verma dil of all chapter of class 9

Sir do you give solutions only for HC Verma or any other book.

Nice