H. C. Verma, Chapter 3, Question number 12 A particle starts from a point A and travels

along the solid curve as shown below. Find approximately the position B of the particle

such that the average velocity between the positions A and B has the same direction as

instantaneous velocity at B. If we assume the B to be at the point shown

by red dot then the net displacement from A to be is along line AB. Since displacement

is along this line, the direction of the average velocity is also along this line. So, the

direction of average velocity between two points on a curve is same as the direction

of chord joining these two points. Also, at B, the direction of instantaneous

velocity is along the tangent to the path at B. To summarize, the direction of average

velocity is along the chord joining A to B and direction of instantaneous velocity is

along the tangent at point B. If direction of both has to be same, then

the direction of chord joining AB must be same the direction of tangent along B. So,

if we draw a line from A such that it is tangent to the curve then the point of contact of

the line with the curve is B. As us can see, in this case the chord and

tangent, both are same and therefore, the direction of average and instantaneous velocity

is same. The coordinate of this point is approximately

3 meter comma 5 meter. This is our answer. In order to request solution to any question

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sir chapter 3 question no.,20, 27, 29, 30 . yeh sb k video hai pr ache se smj nhii aaya hai kia aap kuch help kr skte hai ise video ko improve kr k.. pls reply me fast ..thnk u sir ./

Can a mathematical solution of this question

Sir how you can say 3rd point is b they are opposite in direction

IE erodov solution please

More important than hcv solution

I want the solution of HCV chapter 3 question number 50

sir ans of this ques can be (1.5,3) ???

because in that case both have same direction of velocity

1.1 please Kar dejia